Percentage purity of a sample of gold is 85%.How many atoms of gold are present in its 1gram sample?
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The mass of pure gold in a sample of 1 gram of 85% pure gold is:
85 /100 x 1 = 0.85g
Moles of 0.85 gold:
Moles = mass/molar mass
(Molar mass of gold is 197)
0.85/197 = 0.0043 moles
Avagadros law states that 1 mole of any substance has 6.022
x 10^23 atoms/molecules.
Therefore 0.0043 moles of gold has the following number of atoms:
0.0043 x 6.022 x 10^23
2.598 x 10^21 atoms.
85 /100 x 1 = 0.85g
Moles of 0.85 gold:
Moles = mass/molar mass
(Molar mass of gold is 197)
0.85/197 = 0.0043 moles
Avagadros law states that 1 mole of any substance has 6.022
x 10^23 atoms/molecules.
Therefore 0.0043 moles of gold has the following number of atoms:
0.0043 x 6.022 x 10^23
2.598 x 10^21 atoms.
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