Math, asked by sam3005, 11 months ago

perfect cube of 63000

Answers

Answered by sanjeevkumar20056

0

Answer:

Answer:

The principal, real, root of:

63000√3

=39.7905721

All roots:

39.7905721

−19.895286+34.4596463i

−19.895286−34.4596463i

63000 is not a perfect cube

Answered by rajbirsinghtarar

0

Answer:

40

Step-by-step explanation:

40*40*40, 63000 ihope it is brilliant answer

Previous Question

Next Question

Similar questions

Accountancy, 5 months ago

price of producing revenue is called revenue expense O none of these...

English, 5 months ago

He come to me. He wanted to get some help...

Hindi, 5 months ago

बादल के दो विशेषण शब्द...

English, 11 months ago

What do you mean by a bacteria...

Environmental Sciences, 11 months ago

who is the largest insect in the world...

Math, 1 year ago

it the radius of sphere is 2.1cm then find the volume of sphere?

Math, 1 year ago

if the circumference and area of circle are numericallu equal, then find diameter of circle...

Math, 1 year ago

prove that sinteta/1+costeta+1+costeta/sinteta=2cosecteta...