Question

perimerof triangle with vertices (0,4),(0,0),(3,0) is:
(a)5
(b)12
(c)11
(d)7+root5​

Answer 1

first find length of each sides of ∆

Let A( 4 , 0) B(0, 0) and C (0 , 3)

use distance formula,

AB =√(4²+0) =4

BC= √(0+3²) = 3

CA =√(4²+3²) =5

now ,

perimeter of ∆ = 3 + 4 + 5= 12 unit...

ans is b