perimeter and area of the rectangle are 28 mts and 40 meter square then find the length and bredth
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Let length be l
and, breadth be b
We have, 2(l+b) = 28
so, l+b = 14
so, b = 14-l ........................................(1)
And, l*b = 40
By Eqn (1)
l(14-l) = 40
-l² + 14l - 40 = 0
so, l²-14l + 40 = 0
l²-10l-4l + 40 = 0
l(l-10) -4(l-10) = 0
so, l = 4,10
Hence, b = 10,4
So, We conclude that length and breadth are 10 cm and 4 cm
and, breadth be b
We have, 2(l+b) = 28
so, l+b = 14
so, b = 14-l ........................................(1)
And, l*b = 40
By Eqn (1)
l(14-l) = 40
-l² + 14l - 40 = 0
so, l²-14l + 40 = 0
l²-10l-4l + 40 = 0
l(l-10) -4(l-10) = 0
so, l = 4,10
Hence, b = 10,4
So, We conclude that length and breadth are 10 cm and 4 cm
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