Perimeter and area of the rectangle are 28 mts and 40m² then find its length and breadth
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perimeter of rectangle=2(l+b)
28=2(l+b)
l+b=14 ............. equation (1)
area of rectangle=l*b
40=l*b
l=40/b
put value of l in equation (1)
than we get
40/b+b=14
(40+b^2)=14b
b^2-14b+40=0
solve this equation
b^2-10b-4b+40=0
b(b-10)-4(b-10)=0
(b-4)(b-10)=0
b=4 or b=10
b=4 than l=(40/4)=10
or b=10 than l=4
28=2(l+b)
l+b=14 ............. equation (1)
area of rectangle=l*b
40=l*b
l=40/b
put value of l in equation (1)
than we get
40/b+b=14
(40+b^2)=14b
b^2-14b+40=0
solve this equation
b^2-10b-4b+40=0
b(b-10)-4(b-10)=0
(b-4)(b-10)=0
b=4 or b=10
b=4 than l=(40/4)=10
or b=10 than l=4
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