Question

Perimeter of a rectangle is 15 3/7 if the length is 4 2/7 m find its breadth.

Answer 1

perimeter of rectangle=2(l+b)
108/7=2(28/7+b)
108/7=56/7+b
b=108/7-56/7
b=52/7
b=7 3/7

Answer 2

Answer:

$\frac{24}{7}=3\frac{3}{7}cm$

Step-by-step explanation:

Perimeter of rectangle = $15\frac{3}{7}m$= $\frac{108}{7}m$

Length of rectangle =  $4\frac{2}{7}m$= $\frac{30}{7}m$

Perimeter of rectangle = $2(Length+Breadth)$

So,  $\frac{108}{7}=2(\frac{30}{7}+Breadth)$

 $\frac{108}{7}=2(\frac{30}{7}+Breadth)$

$\frac{108}{7 \times 2}=\frac{30}{7}+Breadth$

$\frac{108}{14}-\frac{30}{7}=Breadth$

$\frac{108-60}{14}=Breadth$

$\frac{48}{14}=Breadth$

$\frac{24}{7}=Breadth$

$\frac{24}{7}=3\frac{3}{7}=Breadth$

Hence the breadth of the rectangle is $\frac{24}{7}=3\frac{3}{7}cm$