Perimeter of a rectangle is 3.4m less than 2/5 of the perimeter of a square. If the perimeter of the square is 40 m, find tje lenght and breadth of the rectangle that breadth is 1/3 of the length
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5
,where l is length and b is breadth.
Suppose the side of a square is S cm
=> Perimeter of square = 4(S) cm
But perimeter of a square is given 40 cm.
=> 4(S) = 40
=>
Suppose the length of a rectangle is L cm.
Since breadth of a rectangle is 1/3 of length,
=> Breadth of a rectangle = 1/3 L cm.
=> Perimeter of rectangle = 2(L + 1/3 L)
=> Perimeter of a rectangle = 8/3 L
Since perimeter of a rectangle is 3.4 less than 2/5 of the perimeter of the square,
=> Perimeter of a rectangle = (2/5) (40)
=> 8/3 L = (2/5) 40 - 3.4
=> 8/3 L = 16 - 3.4
=> 8/3 L = 12.6
=> L = (12.6 × 3)/8
=>
=> 1/3 L = (4.725) (1/3)
=>
Answered by
1
Perimeter(Rectangle) = 2(l+b),where l is length and b is breadth.
\textbf{Perimeter(Square) = 4(side)}Perimeter(Square) = 4(side)
Suppose the side of a square is S cm
=> Perimeter of square = 4(S) cm
But perimeter of a square is given 40 cm.
=> 4(S) = 40
=> \textbf{S = 4 cm}S = 4 cm
Suppose the length of a rectangle is L cm.
Since breadth of a rectangle is 1/3 of length,
=> Breadth of a rectangle = 1/3 L cm.
=> Perimeter of rectangle = 2(L + 1/3 L)
=> Perimeter of a rectangle = 8/3 L
\textbf{According to the question,}According to the question,
Since perimeter of a rectangle is 3.4 less than 2/5 of the perimeter of the square,
=> Perimeter of a rectangle = (2/5) (40)
=> 8/3 L = (2/5) 40 - 3.4
=> 8/3 L = 16 - 3.4
=> 8/3 L = 12.6
=> L = (12.6 × 3)/8
=> \textbf{L = 4.725 cm}L = 4.725 cm
=> 1/3 L = (4.725) (1/3)
=> \textbf{1/3 L = 1.575 cm}1/3 L = 1.575 cm
\textbf{Length of rectangle = 4.725 cm}Length of rectangle = 4.725 cm
\textbf{Breadth of rectangle = 1.575 cm}Breadth of rectangle = 1.575 cm
\textbf{Perimeter(Square) = 4(side)}Perimeter(Square) = 4(side)
Suppose the side of a square is S cm
=> Perimeter of square = 4(S) cm
But perimeter of a square is given 40 cm.
=> 4(S) = 40
=> \textbf{S = 4 cm}S = 4 cm
Suppose the length of a rectangle is L cm.
Since breadth of a rectangle is 1/3 of length,
=> Breadth of a rectangle = 1/3 L cm.
=> Perimeter of rectangle = 2(L + 1/3 L)
=> Perimeter of a rectangle = 8/3 L
\textbf{According to the question,}According to the question,
Since perimeter of a rectangle is 3.4 less than 2/5 of the perimeter of the square,
=> Perimeter of a rectangle = (2/5) (40)
=> 8/3 L = (2/5) 40 - 3.4
=> 8/3 L = 16 - 3.4
=> 8/3 L = 12.6
=> L = (12.6 × 3)/8
=> \textbf{L = 4.725 cm}L = 4.725 cm
=> 1/3 L = (4.725) (1/3)
=> \textbf{1/3 L = 1.575 cm}1/3 L = 1.575 cm
\textbf{Length of rectangle = 4.725 cm}Length of rectangle = 4.725 cm
\textbf{Breadth of rectangle = 1.575 cm}Breadth of rectangle = 1.575 cm
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