perimeter of a rectangle is 32 cm find its maximum possible area if the sides of the rectangle are whole numbers only
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5
Answer:
7
Step-by-step explanation:
Perimeter=2(l+b)
32=2(l+b)
16=l+b
l+b could be
1+15
2+14
3+13
4+12
5+11
6+10
7+9
8+8 would not be the solution as it would form a square
7 possible conditions
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