Perimeter of a rectangle is 44 cm length is increased by 4 cm and breadth is 15352 cm and its area is increased by 72 square cm find the dimensions of the rectangle
Answers
Answered by
1
L=48
B=15352
area=Lxb
x+72=48x15352
now u can solve it
B=15352
area=Lxb
x+72=48x15352
now u can solve it
Answered by
1
Answer:
Perimeter = 44
2 (L + b) = 44
L + b = 22
L = 22-b. (1)
(L+4)(b+2)= Lb+72
Lb + 2L + 4b + 8 = Lb+ 72
2L + 4b + 8 = 72
2L + 4b = 72 - 8
2(L + 2b) = 64
L + 2b = 32
Substitute for L
(22-b) + 2b = 32
22 + b = 32
b = 10 cm
L = 22- b
= 22-10
= 12 cm
So:
Length= 12 cm
Breadth= 10cm
Hope it helps!!!
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