Math, asked by samyakhan9009, 1 day ago

perimeter of a rectangle is 80 m and its length 25 find its breadth and area

Answers

Answered by Itzintellectual
1

Step-by-step explanation:

\tt\red{ QUESTION}\tt\blue{::}

perimeter of a rectangle is 80 m and its length 25 find its breadth and area

\tt\red{ ANSWER}\tt\blue{::}

p = 80m \\ l = 25m \\ 2b = (p - 2l) \\ 2b = 80 - 2(25)m \\ 2b = 80 - 50 \\ 2b = 30 \\ b = 30 \div 2 \\ b = 15

Hence,breadth=\tt\red{ 15}\tt\blue{meter}

l = 25 \\ b = 15 \\ area = (l \times b ) {m}^{2} \\ (25 \times 15) {m}^{2}  \\  = 375m {}^{2}

Hence, area=\tt\red{ 375}\tt\blue{m²}

Answered by XxDashingGirlxX
1

\tt\red{ QUESTION}

perimeter of a rectangle is 80 m and its length 25 find its breadth and area

\tt\red{ ANSWER}

\begin{gathered}p = 80m \\ l = 25m \\ 2b = (p - 2l) \\ 2b = 80 - 2(25)m \\ 2b = 80 - 50 \\ 2b = 30 \\ b = 30 \div 2 \\ b = 15\end{gathered}

Hence,breadth=

\tt\red{ 15}

\begin{gathered}l = 25 \\ b = 15 \\ area = (l \times b ) {m}^{2} \\ (25 \times 15) {m}^{2} \\ = 375m {}^{2} \end{gathered}

\tt\red{ 375}

\tt\blue{m²}

\tt\blue{meter}

\tt\blue{::}

\tt\blue{::}

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