perimeter of a rectangular Park is 56 m . its length is 16 m.find its area. find the cost of levelling it @ rupees 3 per metre square.
Answers
Answered by
18
First find its breadth
breadth = (perimeter ÷ 2 )-length
(56÷2)-16=28-16=12m
breadth is 12m
Now we find the area
Area of a rectangle = length × breadth
= (16×12)m2= 192m2
cost of levelling it =$(192×3)= $576
breadth = (perimeter ÷ 2 )-length
(56÷2)-16=28-16=12m
breadth is 12m
Now we find the area
Area of a rectangle = length × breadth
= (16×12)m2= 192m2
cost of levelling it =$(192×3)= $576
Answered by
12
Perimeter= 2(l+b)
56m= 2(16+b)
56/2 = 16+b
28m= 16+b
28-16m = b
12m=b
Area= l*b
= 16*12 m²
= 192m²
Cost of levelling= Rs. 3* 192
= Rs. 576
56m= 2(16+b)
56/2 = 16+b
28m= 16+b
28-16m = b
12m=b
Area= l*b
= 16*12 m²
= 192m²
Cost of levelling= Rs. 3* 192
= Rs. 576
prabhleen3:
thnx
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