Question

perimeter of a rhombus is 40 metre and length of its diagonal is 12 metre then find its area​

Answer 1

Answer:

96cm2

Step-by-step explanation:

A rhombus has 4 edges of equal length. If it has perimeter of 40cm, then each length would be

40 cm 4 = 10 cm

Divide the rhombus into 4 right-angle triangle by cutting along the 2 diagonals.

Each right-angle triangle will have a hypotenuse of 10cm and one other edge with length

12 cm 2 = 6 cm

Use Pythagoras Theorem to find the length of the remaining edge.

√ ( 10 cm )2 − ( 6 cm ) 2 = 8 cm

Now find the area of the triangle.

1 2 × 6 cm × 8 cm = 24 cm 2

Since the original rhombus was made up of four such triangles, the area of the rhombus would be

24 cm 2 × 4 = 96 cm 2

Answer 2

Answer:

side of rhombus = 40÷4=10

area of rhombus=1/2*10*10√3=50√3 m²