perimeter of a rhombus is 64 cm and its height is 6 CM if length of its one diameter is 16 cm then the length of the diameter is
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Step-by-step explanation:
let abcd is a rhombus.
we know that the adjecent side of rhombus are equal.
so, ab+bc+cd+ad=64cm
so 4ab=64
=>ab=16cm
:.ab=bc=cd=ad=16cm
we know that the diagonals(diameter) bisector each at 90°.
so let the point of intersection be O and the diameter bc=16cm
now in triangle AOB,
using pythagoras theorm,
AB²=(OA)²+(OB)²
16²=(OA)²+8²-------[1/2BC=OB]
256=(OA)²+64
256-64=(OA)²
192=(OA)²
OA=root192
the AD=OA+OD
2root192(ans)
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