Question

perimeter of a rohombus is 260 cm and height is 10 cm if one diagonal is 0.25 m find its area​

Answer 1

perimeter of Rhombus = 260

4a =260

a=65

Area of Rhombus = Base × Height

Base(side) = 65

Height =10cm

A =65×10 =650sq cm

We know that

1/2 × d1×d2 = Area of Rhombus

A= 650

d1= .25 m= 25cm

d2=?

d2= (A×2)/d1

d2=( 650×2)/25

d2= 1300/25=52 cm

So length of other diagonal is 52cm.