Question

perimeter of a semicircular park is 72 M find its area and radius plz urgent

Answer 1

$\pi r + 2r = 72m \: \\ r(\pi + 2) = 72m \\ r = 72m \div \pi + 2 \\ \\ now \\ \\ area \: = \pi {r }^{2} \\ \\ = \pi \times ( {72m)}^{2} \div ( {\pi + 2)}^{2}$

Answer 2

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The radius of the semi circular park is 14 meter.

The area of the semi circular park is 307.72 square meter.

Step-by-step explanation:

Given : If the perimeter of semi circular park is 72 m.

To find : The area and radius of the semi circle ?

Solution :

The perimeter of the semi circular park is P=2r+\pi rP=2r+πr

We have given, P=72

P=r(2+\pi)P=r(2+π)

72=r(2+3.14)72=r(2+3.14)

72=r(5.14)72=r(5.14)

r=\frac{72}{5.14}r=5.1472

r=14r=14

The radius of the semi circular park is 14 meter.

The area of the semi circular park is A=\frac{\pi r^2}{2}A=2πr2

A=\frac{3.14\times 14^2}{2}A=23.14×142

A=\frac{3.14\times 196}{2}A=23.14×196

A=3.14\times98A=3.14×98

A=307.72m^2A=307.72m2

Therefore, The area of the semi circular park is 307.72 square meter.