Perimeter of a square room is 56 m. Another room has one side 2 m more than the first
but has the same perimeter. Find the length and breadth of the second room
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- Perimeter of a square room is 56 m
- Other room has one side 2 m more than the first
- The other room has the same perimeter as that of square room
- Length and breadth of the second room
- Let one side of second room be 'b'
- So , the other side will be 'b + 2'
Clearly the second room is rectangular as the length and breadth differs
➠ P = 2(l + b) ⚊⚊⚊⚊ ⓵
Where ,
- P = Perimeter
- l = Length
- b = Breadth
Given that the perimeter is same as that of square room i.e 56 m
Let length be 'b + 2'
Let breadth be 'b'
So,
- P = 56 m
- l = b + 2
- b = b
⟮ Putting the above values in ⓵ ⟯
➜ P = 2(l + b)
➜ 56 = 2(b + 2 + b)
➜ 56 = 2(2b + 2)
➜ 56 = 4b + 4
➜ 4b = 56 - 4
➜ 4b = 52
➜
➨ b = 13 m
- Hence the breadth of second room is 13 m
Length of second room will be (13 + 2)m
- Hence the length of second room is 15 m
∴ The length and breadth of second room is 15 m & 13 m
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