perimeter of a trapezium is 68cm and its non parallel sides are 12cm each and its altitude is 4cm.find its area
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Perimeter of trapezium= a+b+c+d= 68 cm
a+c=12+12= 24 cm, then b+d=68-24= 44 cm
Area of trapezium
= 1/2 x (a+b) x height= 1/2 x (12+22) x 4=1/2 x 34 x 4 = 68 sq.cm
a+c=12+12= 24 cm, then b+d=68-24= 44 cm
Area of trapezium
= 1/2 x (a+b) x height= 1/2 x (12+22) x 4=1/2 x 34 x 4 = 68 sq.cm
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1
1/2(sum of !! sides ) *height
12*2 +y= 68 , y=44
x=44-8 root 2 =32.68 (sum of !! sides
1/2*36.8*4=65.2 cm2
12*2 +y= 68 , y=44
x=44-8 root 2 =32.68 (sum of !! sides
1/2*36.8*4=65.2 cm2
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