Perimeter of a triangle is 30cm .hypotenuse is 1cm more than one of the perpendicular sides find the length of sides of the triangle
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let the hypotenuse be h then perpendicular side be h-1 and last side be 30-h-(h-1)= 30-2h+1=31-2h
h^2 = (h-1)^2 + (31-2h)^2
solving them we get h=18.5 and h=13
if we take h= 18.5 other side will come in negative.
Hence h=13 h-1=12 31-2h=5
h^2 = (h-1)^2 + (31-2h)^2
solving them we get h=18.5 and h=13
if we take h= 18.5 other side will come in negative.
Hence h=13 h-1=12 31-2h=5
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