perimeter of an isosceles
triangle is 150 m. If its unequal side is 70 m, find the area of the triangle
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Step-by-step explanation:
LET THE TRIANGLE BE ABC
ND LET THE UNEQUAL SIDE BE AC=70M
PERIMETER = AB +BC+AC=150
=AB+BC+70M=150
= 2AB=150-70{other2 sides r eq.}
PERIMERER=2AB=80
=AB=80/2
=AB=40
THERE4 OTHER 2 SIDES R 40M ND 40M
HENCE AREA = 1/2 B×H
1/2 ×40×40
=800m^2
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