Question

perimeter of an isosceles triangle is 32 the ratio of equal side is 3 ratio 2 find the area of triangle​

Answer 1

Isosceles triangle

Solve for area

A≈21.63

b Base

3

P Perimeter

32

Unit Conversion:

Using the formulas

A=bhb

2

P=2a+b

hb=a2﹣b2

4

Solving forA

A=1

4bP(P﹣2b)=1

4·3·32·(32﹣2·3)≈21.63331

Answer 2

the perimeter of isosceles triangle = 32cm

p of isosceles triangle = 2 * equal side + base

let length of equal side be 3x and base be 2x

then

2 * 3x + 2x = 32 cm

6x + 2x = 32cm

8x = 32 cm

x= 4 cm

length of equal side = 3*4= 12cm

length of base = 2*4=8cm

area of isosceles triangle=b*1/4*√4a2-b2

= 8*1/4√4*144-64

=2√512

=2*22.62

= 45.25cm2