Question

perimeter of n isosles triangle is 64 cm and its equal sides are 20 cm . then find its area

Answer 1

step-by-step explanation:

non equal side = 64 - 40 = 24cm

a = base * height/2

height = $\sqrt{20*20 - 12*12}$

           = 16

thus a = 24*16/2 = 192

Answer 2

Answer:

192 cm²

Step-by-step explanation:

Using Hereon's formula...

$\sqrt{s(s-a)(s-b)(s-c)\\}$

where a,b and c are the sides of the given triangle

and s= a+b+c/2

s=64/2

  =32

ATQ,

       =  $\sqrt{32(32-20)(32-20)(32-24)}$

=$\sqrt{(32)(12)(12)(8)}$

=$2*12\sqrt{64}$

=2*12*8

=192 cm²