Question

perimeter of rectangle is 20 and its area is 9 find the length and breadth​

Answer 1

$using \: \: the \: \: fomulas \\ a = w \: l \\ p = 2(l \: + w) \\ there \: are \: two \: solutions \: for \: l \\ l \: = \frac{p}{4} + \frac{1}{4} \sqrt{ {p}^{2} } - 16 \: A \\ = \frac{20}{4} + \frac{1}{4} \sqrt{20}^{2} \: - 16.9 \: = 9 \\ \\ l = \frac{p}{4} - \: \frac{1}{4} \sqrt{p2} \: - 16 \: A \: \\ = \frac{20}{4} - \frac{1}{4} \sqrt{p2} \: - 16.9 \: = \: 1$