perimeter of rectangle is 44cm If its length and breadth is increased by 4cm&2cm respectively its area increases by 72cm^2 find its original dimension
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Answer:
RiyashejiAmbitious
Perimeter = 44
2 (L + b) = 44
L + b = 22
L = 22-b. *****eqn a
(L+4)(b+2)= Lb+72
Lb + 2L + 4b + 8 = Lb+ 72
2L + 4b + 8 = 72
2L + 4b = 72 - 8
2(L + 2b) = 64
L + 2b = 32
Substitute for L
(22-b) + 2b = 32
22 + b = 32
b = 10 cm
L = 22- b
= 22-10
= 12 cm
So:
Length= 12 cm
Breadth= 10cm
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