Math, asked by ironman9374, 7 months ago

perimeter of rectangular swimming pool is 154 its length is 2 metre more than twice its breadth. what are length and breadth of the pool?​

Answers

Answered by Brâiñlynêha
71

\huge\mathbb{SOLUTION:-}

\sf\bullet perimeter= 154m\\ \\ \sf\bullet Breadth =x\\ \\ \sf\bullet Length=2x+2

Now we have to find the length and breadth of pool

\boxed{\dag{\sf{\:\: Perimeter\:of\: rectangle=2(l+b)}}}

\bf\underline{\underline{\red{A.T.Q:-}}}

\sf\implies 2(2x+x+2)=154\\ \\ \sf\implies 3x+2=\cancel{\dfrac{154}{2}}\\ \\ \sf\implies x=77-2\\ \\ \sf\implies 3x= 75\\ \\ \sf\implies x=\cancel{\dfrac{75}{3}}\\ \\ \sf\implies x=25m

\sf\bullet breadth= 25m\\ \\ \sf\bullet length= 2\times 25+2\\ \sf\implies 50+2=52

\boxed{\sf{Length=52m\:\:and\:\: breadth=25m}}


BrainIyMSDhoni: Good :)
Anonymous: Great !
BrainlyConqueror0901: be the best anwerer ever : )
BrainlyConqueror0901: *answerer
BraɪnlyRoмan: Wonderful ✌
Answered by Anonymous
85

\large{\underline{\mathsf{\red{Answer-}}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\underline{\bold{Length\:of\:swimming\:pool\:is\:52\:m.}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\underline{\bold{Breadth\:of\:swimming\:pool\:is\:25\:m.}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\large{\underline{\mathsf{\red{Explanation-}}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\begin{lgathered}\bold{Given} \begin{cases}\sf{Perimeter\:of\:rectangular\:pool\:=\:154\:m} \\ \sf{Length\:is\:2\:m\:more\:than\:twice\:its\:breadth}\\ \sf{Length\:and\:breadth\:of\:pool\:=\:?}\end{cases}\end{lgathered}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\sf{Let\:breadth\:of\:pool\:be\:B}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀\small{\sf{\purple{(According\:to\:the\:question-)}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\sf{Length\:=\:2B\:+\:2} ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀– eq (1)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

We know that,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\large{\boxed{\blue{\sf{Perimeter\:of\:rectangle\:=\:2(L+B)}}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀\small{\pink{\sf{(Putting\:the\:values-)}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{154\:=\:2(2B\:+\:2\:+B)}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{154\:=\:4B\:+\:4\:+\:2B}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{154\:-\:4\:=\:6B}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{6B\:=\:150}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{B\:={\cancel{\dfrac{150}{6}}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{B\:=\:25\:m}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\therefore \underline{\bold{Breadth\:of\:swimming\:pool\:is\:25\:m.}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\rule{200}2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\sf{Now,\:put\:the\:value\:of\:B\:in\:eq\:(1)}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{Length\:of\:pool\:=\:2(25)\:+\:2}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{Length\:of\:pool\:=\:50\:+\:2}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

: \implies \sf{Length\:of\:pool\:=\:52\:m}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\therefore \underline{\bold{Length\:of\:swimming\:pool\:is\:52\:m.}}


BrainIyMSDhoni: Great :)
Rythm14: kamaal xD
Anonymous: Awesome !
VishalSharma01: Great Answer :)
BrainlyConqueror0901: keep it up ♡
BraɪnlyRoмan: Wonderedful ✌
Anonymous: Keep it up mate:)
Anonymous: Keep it up Awesome
Similar questions