Question

Perimeter of rhombus is 34 cm and sum of its diagonals is 23 cm . What will be the area of rhombus

Answer 1

Answer:

Step-by-step explanation:

First u should know the properties of rhombus.

For this question u need to know these 2 properties:

1. All sides of rhombus are equal.

2. Diagonals of rhombus bisect each other.

Now, let’s come to the question.

For understanding this question we will take help of this rhombus

According to question,

AC= 24 cm and BD=10 cm

we need to find the perimeter

AE=EC=12 cm and BE=ED=5 cm (Property 2)

Now, in triangle AED, By Pythagoras Theorem

AD^2= AE^2 + ED^2

AD^2= 12^2 + 5^2

AD^2= 144 + 25

AD^2= 169

AD = 13 cm

Perimeter = AB+BC+CD+DA = 13+13+13+13= 52cm (Property 1)

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