perimeter of square is 28root2 find diagonal
Answers
Let the given square be ABCD.
Perimeter of square=28√2....... (Given)
since we know that,
Perimeter of a square=4×side
Let the side of the square be x.
28√2=4x
28√2/4=x
therefore, x=7√2
therefore, side of the square be 7√2
let AB=CD=7√2.....( All sides of square are congruent)
let AC be the diagonal of the square.
<A=<B=<C=<D=90°........ (Angles of a square)
therefore in triangle ABC, <ABC=90°
therefore, by Pythagoras thearom,
(AB) ²+(BC) ²=(AC) ²
(7√2) ²+(7√2) ²=(AC) ²
(AC) ²=98+98
(AC) ²=196
AC=14
therefore, diagonal of the square us 14
Answer:
The diagonal of square is 14 units.
Step-by-step-explanation:
NOTE: Kindly refer to the attachment first.
In fig., ⎕ ABCD is a square. [ Given ]
[ Given ]
We know that,
Additional Information:
1. Square:
A two dimensional figure having four equal sides and four angles of measurement 90° is called a square.
2. Perimeter:
The sum of lengths of the all sides of a particular figure is called perimeter.
3. Perimeter of square:
The perimeter of square means the sum of lengths of all sides of the square.
4. Formula for perimeter of square:
5. Diagonal of square:
The line segment joining the two opposite corners ( angles ) of the square is called a diagonal of square.
6. Formula for diagonal of square: