Question

PERIMETER OF THE SECTOR?? please helppp :(

Answer 1

Answer:

solve it further...i am busy

Step-by-step explanation:

perimeter of sector

2×radius +lenght of arc

20 + 135/360 ×2 ×22/7 ×10× 10

Answer 2

$arc \: length = radius \times angle \\ \\ make \: sure \: that \: the \: angle \: is \: in \\ radians...... \\ \\ total \: angle = 135 \\ in \: radian = 135 \frac{\pi}{180} \\ \\ angle = \frac{3\pi}{4} \\ \\ \pi = 3.14 \\ \\ angle = 2.355(aprox) \\ \\ perimeter \: of \: sector \: = 2 \times radius \times angle \\ perimeter \: of \: sector = 2 \times 10 \times 2.355 \\ \\ perimeter \: of \: sector = 4.71 \times 10 \\ \\ finally \: the \: answer \: is \: 47.1 {cm}^{2}$

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