perimetere of a rectangle is 108/7 m . if length is 30/7 m find the breadth
Answers
Answered by
66
hiii!!!
here's ur answer...
given the Length of the rectangle is 30/7m.
perimeter of the rectangle = 108/7m
therefore 2 ( l + b ) = 108/7m
==> 2 ( 30/7 + b ) = 108/7m
==> 30/7 + b = 108/7 × 1/2
==> 30/7 + b = 54/7
==> b = 54/7 - 30/7
==> b = 24/7m
VERIFICATION :-
perimeter of the rectangle = 2 ( l + b )
= 2 ( 30/7 + 24/7 )
= 2 × 54/7
= 108/7m
hence verified
thus the breadth of the rectangle is 24/7m
hope this helps..!!
here's ur answer...
given the Length of the rectangle is 30/7m.
perimeter of the rectangle = 108/7m
therefore 2 ( l + b ) = 108/7m
==> 2 ( 30/7 + b ) = 108/7m
==> 30/7 + b = 108/7 × 1/2
==> 30/7 + b = 54/7
==> b = 54/7 - 30/7
==> b = 24/7m
VERIFICATION :-
perimeter of the rectangle = 2 ( l + b )
= 2 ( 30/7 + 24/7 )
= 2 × 54/7
= 108/7m
hence verified
thus the breadth of the rectangle is 24/7m
hope this helps..!!
Answered by
4
Answer:
=24/7
Step-by-step explanation:
Let the breadth be x
perimeter=2(l+b)=108/7
=> 2(30/7+x)=108/7
=> (30/7+x)= 54/7
=> x=54/7 - 30/7
=> x= (54-30)/7
=> x= 24/7 ans.
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