perimetre of triangle is 180m and sides are 9:40:41 find the area of triangle
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therefore the area738cm.sq
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let the sides be 9x,40x,41x
perimeter =9x+40x+41x=180
90x=180
x= 2
sides will be 18,80,82
by heron's formula
s= 180/2 = 90
ar = √s(s-a)(s-b)(s-c)
ar=√90(90-18)(90-80)(90-82)
and solve it yrself .........
perimeter =9x+40x+41x=180
90x=180
x= 2
sides will be 18,80,82
by heron's formula
s= 180/2 = 90
ar = √s(s-a)(s-b)(s-c)
ar=√90(90-18)(90-80)(90-82)
and solve it yrself .........
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