Question

Period of oscillations of mass M suspended from spring of negligible mass T if another nasser suspended along it period of oscillations becomes

Answer 1

Answer:

period of oscillations becomes $\sqrt{2T}$

Explanation:

Time period of simple pendulum $T=2\pi \sqrt{ \frac{M}{k} }$

where M is the mass , k is the stiffness of the spring

Another mass M is added, then time period becomes

$T^'=2\pi \sqrt{ \frac{M+M}{k}}\\T^'=2\pi \sqrt{ \frac{2M}{k} }$

$T^' =\sqrt{2T}$