Question

Period of sec²x-tan²x=?

p.s: please don't give silly answers like sec²x-tan²x=1, I'm asking the period not its value!​

Answer 1

period of sec²x and tan²x is π

therefore period of sec²x-tan²x is the LCM of the periods of sec²x and tan²x

ie π itself

alternate method:

sec²x-tan²x=sec²(T+x)-tan²(T+x)

on solving or just by observation

T=π

hope this isn't a silly answer...XD

#FingersCrossed

XD

Answer 2

$hi \: ...$

here's your answer ,..

The period of

${sec}^{2} x \: - \: {tan}^{2} x$

is π .

$hope \: \: \: this \: \: helps \: ...$