Periodic acid splits glucose and fructose into formic acid and formaldehyde. Ratio of formic acid and formaldehyde from glucose and fructose is :
a) 5/1 and 4/2
b) 5/1 and 3/2
c) 4/2 and 4/2
d) 3/2 and 4/2
The correct answer as per given in the book is option b) . Please explain how it is ?????
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Hello dear,
● Answer - b) 5/1 And 3/2
● Explaination-
- Periodic acid (HIO3) cleaves the carbon-carbon bond in sugar through oxidation.
- 1 molecule of glucose will break into 5 formic acid, 1 formaldehyde. Thus formic acid/formaldehyde ratio is 5/1.
- 1 molecule of fructose will break into 3 formic acid, 2 formaldehyde and 1 carbon dioxide. Thus formic acid/formaldehyde ratio is 3/2.
Hope this is useful...
● Answer - b) 5/1 And 3/2
● Explaination-
- Periodic acid (HIO3) cleaves the carbon-carbon bond in sugar through oxidation.
- 1 molecule of glucose will break into 5 formic acid, 1 formaldehyde. Thus formic acid/formaldehyde ratio is 5/1.
- 1 molecule of fructose will break into 3 formic acid, 2 formaldehyde and 1 carbon dioxide. Thus formic acid/formaldehyde ratio is 3/2.
Hope this is useful...
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