Question

perpendicular distance of the point ( 3,5,7 ) from the y axis is? give solutions​

Answer 1

Answer:

The perpendicular distance of a point from the x-axis is it’s y-coordinate and the perpendicular distance of a point from the y-axis is the x-coordinate.

Complete step-by-step answer:

A coordinate system is a system that uses one or more numbers, also called the coordinates, to uniquely determine the position in space.

A cartesian coordinate system in a two-dimensional plane is a set of two perpendicular lines and the points are represented by the perpendicular distance from these coordinates. The origin is the intersection of these two perpendicular lines and assigned a value of (0, 0).

In this problem, we are given a point P with coordinates (5, 7). We need to determine the perpendicular distance of this point from the y-axis.

The perpendicular distance of a point from the x-axis is it's y-coordinate and the perpendicular distance of the point from the y-axis is its x-coordinate as per definition.

The x-coordinate of the point P is 5. The y-coordinate of the point P is 7.

Hence, the perpendicular distance of the point P from the y-axis is 5 units.

Note: You need to be careful, you might think the y-coordinate is the perpendicular distance from the y-axis but it is not, the x-coordinate is the perpendicular distance from the y-axis.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

P=(3,5,6) Q=(0,5,0)

perpendicular distance=

$\sqrt{ ({x1}^{2} - {x2}^{2}) + ( {y1}^{2} - {y2}^{2} ) + ( {z1}^{2} - {z2}^{2} ) } \\ = \sqrt{ {3}^{2} + 0 + {7}^{2} } \\ = \sqrt{9 + 49} \\ = \sqrt{58}$