perpendicular to each other.
. Find the area of the shaded region in the figures given below.
(i)
A
D
(ii)
14 cm
P
7 cm
32
Q
15 cm
10 cm
8 cm
T
6 cm
B
10 cm
P5cm
S
R
Answers
Answered by
1
Answer:
Where is the image?
the alignment of your question is also not proper can you make it proper so that I can give you the right answer.
Answered by
1
Answer:
Given: Radius of inner circle =7 cm
Radius of outer circle =14 cm
Angle made by sector = 40
o
Area of sector OAC =
360
o
40
o
×πr
2
=
9
1
××
7
22
×14
2
=68.44
Area of sector OBD =
360
o
40
o
×πr
2
=
9
1
××
7
22
×7
2
=17.11
Area of the small region ABDC = Area of the small sector OAC – Area of the small sector OBD
Area of shaded region ABDC= Area of outer circle − Area of inner circle − area of small region ABCD
Area of shaded region ABDC=π×14
2
−π×7
2
−17.11 cm
2
Area of shaded region ABDC=444.704 cm
2
Step-by-step explanation:
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