Question

person moves from town A to town B with speed v and returns back to town A from town B along the same path with speed 3v. The average speed of person is​

Answer 1

Answer:

= 3v-v/t

Explanation:

average speed= V2-V1/t

=3V - V / t

Answer 2

Answer:

The average speed of the person is​ $\frac{3v}{2}$.

Explanation:

The average speed of the person is given as,

$V=\frac{D}{T}$        (1)

Where,

V=average speed

D=total distance

T=total time taken

Let the distance traveled by the person from A to B be "d".So, the total distance traveled will be "2d".

And the total time taken is calculated as,

$T=t_1+t_2$        (2)

For t₁

$t_1=\frac{d}{v_1}$    (3)

By taking the required values from the question we get;

$t_1=\frac{d}{v}$      (4)

For t₂

$t_2=\frac{d}{v_2}$   (3)

By taking the required values from the question we get;

$t_2=\frac{d}{3v}$    (5)

By inserting equations (4) and (5) in equation (2) we get;

$T=\frac{d}{v}+\frac{d}{3v}$

$T=\frac{4d}{3v}$        (6)

Now by placing the values in equation (1) we get;

$V=\frac{2d}{\frac{4d}{3v}}$

$V=\frac{3v}{2}$

Hence, the average speed of the person is​ $\frac{3v}{2}$.

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