Question

person travelled from one end A to the other end B of a straight 200 m road in 2 minutes and then returns around and travelled 100-meter back to point C in another 1 minute its average speed is​

Answer 1

From A to B

Time for A => B =2 mins

= 2 × 60 sec

= 120 sec

Average speed=

$\frac{total \: distnce}{total \: interval}$

$= \frac{200}{120} \\ = 1.6m/ s$

See in attachment

Answer 2

Avergage speed=total distance travelled/total taken time

total distance travelled=200+100=300m

take take =3×60=180

average speed=300/180=1.6m/s