Question

person X moves from point a to point b with uniform speed 30 kilometre b2a with 60 km then average speed is dash into 10 ^ 1 middle per second​

Answer 1

person X moves from point a to point b with uniform speed 30 km/h b to a with 60 km/h then average speed is __ × 10¹ m/s .

solution : Let distance between a and b is L

then, time taken by person X to move from a to b, t1 = L/30 hrs

again, time taken by person X to move from b to a, t2 = L/60 hrs.

so, total time taken = t1 + t2

= (L/30 + L/60) hrs.

and total distance covered by person X = (L + L) = 2L

now average speed = total distance/total time taken

= (2L)/(L/30 + L/60)

= (2 × 30 × 60)/(30 + 60)

= (60 × 60)/(90)

= 40 km/h

we know, 1 km/h = 5/18 m/s

so, 40 km/h = 40 × 5/18 = 100/18

= 5.55 m/s

= 0.555 × 10¹ m/s

hence, in place of dash, 0.555 should be placed.