Question

Peter gave one-fourth of the amount he had to Mitchel. Mitchel in turn gave
half of what he received from Peter to Sam. If the difference between the
remaining amount with Peter and the amount received by Sam is 500, how
much money did Mitchel receive from Peter ?​

Answer 1

Answer:

The answer is 200.

Hope this helps you.

Answer 2

Money Mitchel received from Peter = 200

• If the amount Peter had was X
• The amount Peter gave to Mitchel is X/4
• The amount that Mitchel gave to Sam is (1/2)x(X/4) = X/8
• The amount remaining with Peter will be 3X/4
• The difference between the  remaining amount with Peter and the amount received by Sam is (3X/4)-(X/8) = 5X/8 = 500
• Therefore, X = 500 x 8/5 = 800
• i.e., Amount Mitchel received = 800/4 = 200