PG is twice as old as his brother Deepu if the difference of their ages is 11 years find the present age
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Deepu's age = x
PG's age = 2x
Difference of their ages 11
=> 2x - x = 11
=> x = 11
PG's age = 2x = 2×11 = 22
Deepu's age = 11
PG's age = 22
PG's age = 2x
Difference of their ages 11
=> 2x - x = 11
=> x = 11
PG's age = 2x = 2×11 = 22
Deepu's age = 11
PG's age = 22
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