Question

pH=5
[H2​O]+=10−pH;LetV1​=x,V2​=100x,M2​=?
According to dilution law,
M1​V1​=M2​V2​
10−5x=M2​100x
100x10−5x​=M2​ or M2​=10−7
[H3​O+]=10−7+10−7 M from water
$$ -2 \times 10^{-7}\, M$$
pH=−log[H3​O+]=−log(2×10−7)=6.69
Hence, solution becomes almost neutral.

ans.....kashishb524 ​

Answer 1

Answer:

pH=5

[H2O]+=10−pH;LetV1=x,V2=100x,M2=?

According to dilution law,

M1V1=M2V2

10−5x=M2100x

100x10−5x=M2 or M2=10−7

[H3O+]=10−7+10−7 M from water

$$ -2 \times 10^{-7}\, M$$

pH=−log[H3O+]=−log(2×10−7)=6.69