pH of 0.005 M H2So4 solution is
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the ph of 0.005 M of H2So4 is 2
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Answer:
2
Explanation:
chemical eq: H2SO4⇒2H+ +SO4 2-
pH =-log(H+)
therefore: H+ = 2H+
pH = -log (2H+)
= -log (2 x 0.005)
=-log ( 0.001)
=2
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