Chemistry, asked by SauravJais3176, 1 year ago

Ph of 0.01m acetic acid with degree of dissociation 1.25%

Answers

Answered by nagathegenius

0

Answer:

Explanation:

h plus = 0.01*.0125

=.000125

ph=-log h plus

=-log 125/10^6

- { 2.07-6}

-{-3.93}

3.93

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