Question

The sum of three consecutive multiples of 13 is 819. Find these multiple.

Answer 1

Step-by-step explanation:

let first number be x

let the second number be x+13

let the third number be x+26

x+x+13+x+26=819

3x+39=819

3x=819-39

3x=780

x=780/3

x=260

the first number is 260

the second number is 273

the third number is 286

hope it is useful

Answer 2

Let the first consecutive multiple be 13x.

Second consecutive multiple = ( 13x + 13 )

Third consecutive multiple = ( 13x + 26 )

13x + ( 13x + 13 ) + ( 13x + 26) = 819

39x + 39 = 819

39x = 819 - 39

39x = 780

x = 780/39

x = 20

Hence, the three consecutive multiples of 13 are :-

13x = 13 × 20 = 260

13x + 13 = 13 × 20 + 13

= 260 + 13

= 273

13x + 26 = 13 × 20 + 26

= 260 + 26

= 286

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