ph of 0.05 m ca(oh)2
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Answer:
pH = 13
Explanation:
Ca(oH)2 is acidic base . so it's normality is 0.1 .
POH = - log (0.1)
PoH = 1
since pH+PoH = 14
pH= POH - PH
PH = 14-1= 13
PH = 13
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