Question

pH of 0.05 monobasic acid is 6.2. The % dissociation of it is?

A) 1.29
B) 0.029
C) 2.12
D) 0.04

Please answer​

Answer 1

Explanation:

ph=6.2

so, Ka=10^-6.2 .......... {^}denotes = power

Now, dissociation =√Ka/concentration

=√10^-6.2/0.05

approximately =0.004

so, %=0.004*100

=0.4

This is correct answer.

please recheck your options.