Question

ph of 10^-2 M h2so4 solution is..

Answer 1

Ph of a solution is negative logarithm of its concentration so

Ph = -log( 10power-2)

= -(-2)

= 2

Therefore ph is two

Answer 2

Answer: 1.7

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

$10^{-2}MH_2SO_4$

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

1 mole of $H_2SO_4$ dissociates to form 2 moles of $H^+$

$10^{-2}H_2SO_4$ dissociates to form $2\times 10^{-2}=0.02$ moles of $H^+$

$pH=-\log [0.02]$

$pH=1.7$

Thus pH of the solution is 1.7.