Question

ph of 10^-3M h2so4 solution is..

Answer 1

• We calculate that how many free hydrogens are present in H₂SO₄. Now we know it will ionise as 2H⁺ and 1 SO₄²⁻ . thus one molecule can release 2H+ in an aqueous soln

• Now we calculate the concentration of H+ ions so if there's 10⁻³ M of H₂SO₄ after dissolving it will be 2 × 10⁻³ of it

• Finally we calculate the pH as we know it the negative of log of the H+ concentration for this case it would be -log(2 × 10⁻³)= 3 - log2 ≈ 2.69

• Thus pH of the given soln ≈2.69