pH of 10^-8 M NIOS solution
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REASON:-
Concentration of OH- ion in NaOH is 10^-8M.
Formula pOH = -log[OH-]
Therefore, pOH=-(-8)=8
pH= 14-pOH
pH= 6
But here NaOH is aqueous solution so it contains some amount of H2O hence its pH decreases.
Therefore revised answer is :-
total concentration OH- = 1 x 10^-7 + 1 x 10^-8 =1.1 x 10^-7 M
pOH = 6.96
pH = 14 - 6.96 =7.04
Concentration of OH- ion in NaOH is 10^-8M.
Formula pOH = -log[OH-]
Therefore, pOH=-(-8)=8
pH= 14-pOH
pH= 6
But here NaOH is aqueous solution so it contains some amount of H2O hence its pH decreases.
Therefore revised answer is :-
total concentration OH- = 1 x 10^-7 + 1 x 10^-8 =1.1 x 10^-7 M
pOH = 6.96
pH = 14 - 6.96 =7.04
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