pH of a 5 × 10–6M Ba(OH)2 solution is
Answers
Answered by
9
Hello dear,
● Answer -
pH = 5.301
● Explanation -
# Given -
Concentration = 5×10^-6 molar
# Solution -
pH is nothing but negative base 10 logarithm of hydrogen ion concentration in a solution.
pH of the solution is calculated by formula.
pH = -log(concentration)
pH = -log(5×10^-6)
pH = 5.301
Hence, pH of given Ba(OH)2 soln is 5.301.
Hope this helped...
● Answer -
pH = 5.301
● Explanation -
# Given -
Concentration = 5×10^-6 molar
# Solution -
pH is nothing but negative base 10 logarithm of hydrogen ion concentration in a solution.
pH of the solution is calculated by formula.
pH = -log(concentration)
pH = -log(5×10^-6)
pH = 5.301
Hence, pH of given Ba(OH)2 soln is 5.301.
Hope this helped...
Answered by
9
Answer:9
Explanation:on-site of the solution is = 2× 5×10^-6 =10^1×10^-6
=10^-5
Poh=-log[oh-]
Poh=- log[10^-5]
So,poh=5×log10 [log10=1]
》poh=5 ---------> [1]
Ph+poh=14
From [1]
Ph+5=14
Ph=14-5=9
So,ph=9
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