Question

ph of a buffer solution containing 0.15 moles of NH4OHand 0.4 moles of NH4Cl . Kb for NH4OH is 1.98×10^-5 . Then the buffer solution is approximately equals to​

Answer 1

Answer:

Applying the equation

pOH=log[Salt]/[Base]−logKb

= log(0.4/0.15)-log(1.98×10^-5)

= 5.129

Therefore, pH of buffer solution is (14 - 5.129) = 8.871